gareth3ying
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 |  Subject: Analytical Geometry  Mon Jan 07, 2008 9:49 pm | |
| length of the perpendicular from (3,2) on the line 3x+2y+1=0. | |
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gareth3ying
Adminstrator of 3/4 Hummies Forum
Number of posts : 194
Age : 31
Location : In 4 Hummies forum !! Where I LIVE
Humor : I have no Gender !! YAY I'M a SUB SPECIES
Registration date : 2007-12-05
| | Subject: Reply Mon Jan 07, 2008 9:52 pm | |
| Write the line in slope intercept form: y=\frac{-3x}{2}-\frac{-1}{2}
Since slopes of perpendicular lines are negative reciprocals, the perpendicular line is in the form y=\frac{2x}{3}+b
Substituting (3,2) in, we find b=0 so the line is y=\frac{2x}{3} | |
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